Cove is a census-designated place (CDP) in Cache County, Utah, United States. The population was 460 at the 2010 census. It is included in the Logan, Utah-Idaho Metropolitan Statistical Area.
According to the United States Census Bureau, the CDP has a total area of 14.6 square miles (37.8 km), all of it land.
As of the census of 2000, there were 433 people, 116 households, and 103 families residing in the CDP. The population density was 29.5 people per square mile (11.4/km²). There were 123 housing units at an average density of 8.2/sq mi (3.2/km²). The racial makeup of the CDP was 92.33% White, 0.23% Native American, 0.45% Asian, 3.39% from other races, and 3.61% from two or more races. Hispanic or Latino of any race were 3.39% of the population.
There were 116 households out of which 57.8% had children under the age of 18 living with them, 85.3% were married couples living together, 0.9% had a female householder with no husband present, and 11.2% were non-families. 10.3% of all households were made up of individuals and 7.8% had someone living alone who was 65 years of age or older. The average household size was 3.82 and the average family size was 4.15.
In the CDP, the population was spread out with 43.6% under the age of 18, 8.1% from 18 to 24, 24.8% from 25 to 44, 14.7% from 45 to 64, and 8.8% who were 65 years of age or older. The median age was 21 years. For every 100 females, there were 89.3 males. For every 100 females age 18 and over, there were 100.0 males.
The median income for a household in the CDP was $50,667, and the median income for a family was $51,083. Males had a median income of $43,000 versus $31,250 for females. The per capita income for the CDP was $12,316. About 9.5% of families and 15.6% of the population were below the poverty line, including 24.1% of those under age 18 and none of those age 65 or over.