Ballard (/ˈbælərd/ BAL-ərd) is a town in Uintah County, Utah, United States. The population was 566 at the 2000 census, a decrease of 78 persons from the 1990 population of 644.
According to the United States Census Bureau, the town has a total area of 14.0 square miles (36.3 km²), all of it land.
As of the census of 2000, there were 566 people, 181 households, and 146 families residing in the town. The population density was 40.4 people per square mile (15.6/km²). There were 196 housing units at an average density of 14.0 per square mile (5.4/km²). The racial makeup of the town was 95.41% White, 0.18% African American, 3.00% Native American, 0.53% from other races, and 0.88% from two or more races. Hispanic or Latino of any race were 1.41%.
There were 181 households out of which 47.0% had children under the age of 18 living with them, 70.7% were married couples living together, 3.9% had a female householder with no husband present, and 19.3% were non-families. 18.2% of all households were made up of individuals and 7.7% had someone living alone who was 65 years of age or older. The average household size was 3.13 and the average family size was 3.58.
In the town, the population was spread out with 34.6% under the age of 18, 10.2% from 18 to 24, 26.5% from 25 to 44, 20.3% from 45 to 64, and 8.3% who were 65 years of age or older. The median age was 30 years. For every 100 females, there were 108.9 males.
The median income for a household in the town was $35,278, and the median income for a family was $36,484. Males had a median income of $29,875 versus $17,361 for females. The per capita income for the town was $12,620. About 7.7% of families and 8.5% of the population were below the poverty line, including 6.8% of those under age 18 and 17.0% of those age 65 or over.